Answer:
510 gorillas
Explanation:
In this problem, the population of gorillas is decreasing at a rate of 3.5 % per year.
We can write an expression for the population of gorillas as follows:
![n(t) = n_0 (1+r)^t](https://img.qammunity.org/2021/formulas/mathematics/high-school/ie7zyat2nb6j3yyg29c1oaho7zq7jbcws9.png)
where
n(t) is the number of gorillas after t years
is the number of gorillas at t = 0
r is the grow rate of the population
t is the number of years
Here we have:
is the number of gorillas when t = 20 years
is the grow rate of the population
So the equation becomes:
![250 = n_0 (1-0.035)^(20) = n_0 (0.965)^(20)](https://img.qammunity.org/2021/formulas/mathematics/high-school/11wvleh542dur7oeki4cgnxbclhcnzq9bd.png)
And solving for
, we find the initial number of gorillas:
![250=n_0 (0.965)^(20)=n_0 \cdot 0.490\\n_0 = (250)/(0.490)=510](https://img.qammunity.org/2021/formulas/mathematics/high-school/mywffi8wld81ir9ijbj7jiiverutd9bs1x.png)