Answer: The amount of hydrogen gas collected will be 0.073 g
Step-by-step explanation:
We are given:
Vapor pressure of water = 23.78 mmHg
Total vapor pressure = 740 mmHg
Vapor pressure of hydrogen gas = Total vapor pressure - Vapor pressure of water = (740 - 23.78) mmHg = 716.22 mmHg
To calculate the amount of hydrogen gas collected, we use the equation given by ideal gas which follows:

where,
P = pressure of the gas = 716.22 mmHg
V = Volume of the gas = 0.947 L
T = Temperature of the gas =
![25^oC=[25+273]K=298K](https://img.qammunity.org/2021/formulas/chemistry/college/h90rloyf77jo1jed7el4n760wq4iuiuecg.png)
R = Gas constant =

n = number of moles of hydrogen gas = ?
Putting values in above equation, we get:

To calculate the mass from given number of moles, we use the equation:

Moles of hydrogen gas = 0.0365 moles
Molar mass of hydrogen gas = 2 g/mol
Putting values in above equation, we get:

Hence, the amount of hydrogen gas collected will be 0.073 g