Question

How many atoms in total are present in sucrose C12H2011 weighs 1.4 mg

Answer 1

2.46×10²¹atoms

Step-by-step explanation:

`molar \: mass \: of \: the \: sucrose = 12(12) + 22(1) + 11(16) \\ = 144 + 22 + 176 \\ = 342g {mol}^( - 1) \\ mole = \frac{1.4 * {10}^( - 3) }{342} \\ = 4.09 * {10}^( - 6) \\ number \: of \: atoms = 4.09 * {10}^( - 6) * 6.022 * {10}^(23) \\ = 2.46 * {10}^(21) atoms`