Answer:
The minimum distance moved by mirror is 125 nm
Step-by-step explanation:
Given:
Wavelength of light
m
Here given in question, spot of constructive interference change to a destructive interference.
Hence minimum distance moved by one of mirror is given by,
Where
distance moved by mirror
![t = (\lambda )/(4)](https://img.qammunity.org/2021/formulas/physics/college/zrackarxn7vyzy3rvnxcoagn6kl1ec55kv.png)
![t = (500* 10^(-9) )/(4)](https://img.qammunity.org/2021/formulas/physics/college/9z44x7bhzv68gqkddd5ujci3mkwj1tuu4i.png)
![t = 125 * 10 ^(-9)](https://img.qammunity.org/2021/formulas/physics/college/tyw2ifwlk8lpo89bvix885dtxlvn9zsl2o.png)
Therefore, the minimum distance moved by mirror is 125 nm