Question

An Aiken High school track athlete is participating in the 100-meter hurdle event. If the

runner's initial vertical jump is 2.0 m/s, how much will the runner's center of mass be
raised during the jump?

Answer 1

Center of mass of the athlete will reach to maximum height of 20 cm

Step-by-step explanation:

Here we know that initial speed of the athlete in vertical direction is given as

`v_y = 2 m/s`

now we know that acceleration due to gravity will oppose its motion in opposite direction

so we have

`v_f^2 - v_i^2 = 2 a d`

so when it reach maximum height the final speed becomes zero

so we have

`0 - 2^2 = 2(9.81)H`

`H = 0.20 m`