Question

A sample of krypton gas in a container of volume 1.90 L exerts a pressure of 0.553 atm at 21 Celsius. How many moles of gas are present?

Answer 1

The number of moles of gas present in the sample is 0.0436 mol.

Step-by-step explanation:

To determine the number of moles of gas present in the sample, we can use the Ideal Gas Law equation: PV = nRT.

Given: P = 0.553 atm, V = 1.90 L, T = 21 °C = 273.15 + 21 = 294.15 K.

Using the Ideal Gas Law, we can solve for n:

n = PV / RT

Substituting the given values into the equation:

n = (0.553 atm)(1.90 L) / (0.0821 L·atm/mol·K)(294.15 K)

Simplifying the equation gives us n = 0.0436 mol.

Answer 2

0.044 mole

Step-by-step explanation:

Data obtained from the question include:

V (volume) = 1.90 L

P (pressure) = 0.553 atm

T (temperature) = 21°C = 21 + 273 = 294K

R (gas constant) = 0.082atm.L/Kmol

n (number of mole of krypton) =?

Using the ideal gas equation PV = nRT, the number of mole of krypton can obtained as illustrated below:

PV = nRT

n = PV /RT

n = (0.553 x 1.9)/(0.082x294)

n = 0.044 mole

Therefore, 0.044 mole of krypton is present in the container.