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A 2.3-kg toy locomotive is pulling a 1.0-kg caboose. The frictional force of the track on the caboose is 0.48 N backward along the track. If the train is accelerating forward is 2.6 m/s2, what is the magnitude of the force exerted by the locomotive on the caboose

2 Answers

2 votes

Answer:

Force applied will be equal to 3.4 N

Step-by-step explanation:

We have given mass of the toy is pulling 1 kg caboose

So m = 1 kg

Frictional force f = 0.48 N

Acceleration
a=2.6m/sec^2

Let the force exerted is F

So
F-F=ma, here F is force applied f is frictional force m is mass and a is acceleration

So F = f+ ma


=0.8+1* 2.6=3.4N

So force applied will be equal to 3.4 N

User Christoph Strasen
by
7.7k points
5 votes

Answer:

The magnitude of the force exerted by the locomotive on the caboose is 3.08 N.

Step-by-step explanation:

Given that,

Mass of a toy, m = 2.3 kg

Mass of caboose, m' = 1 kg

The frictional force of the track on the caboose is 0.48 N backward along the track.

The acceleration of train,
a=2.6\ m/s^2

The magnitude of the force exerted by the locomotive on the caboose is given by :


F=m'a+f\\\\F=1* 2.6+0.48\\\\F=3.08\ N

So, the magnitude of the force exerted by the locomotive on the caboose is 3.08 N.

User Jagge
by
8.1k points
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