The values are x= 0 and y= -3.
Explanation:
The given equations are,
6x-5y=15...........................(1)
x=y+3................................(2)
Step:1
Modify the equation (2) in (x+y=constant) format,
x-y=3................................(3)
Step:2
The equation (3) is multiplied by 5 (5×Eqn(3))
5x-5y=15........................(4)
Step:3
Subtract the equation (1) and (4)
6x-5y=15.......................(1)
5x-5y=15.......................(4)
( - ) (∵ Eqn(1)-Eqn(4))
(6x-5x)+(-5y+5y)=(15-15)
(x)+(0)=(0)
x=0
Step:4
Substitute the X=0 in the equation (2),
x=y+3............................(2)
(∵ x=0)
0=y=3
y=-3
Step:5
Check for solution substitute values of X and Y in equation (1),
6x-5y=15...........................(1)
(∵ x=0, y=-3)
(6×0)-(5×(-3))=15
15=15
Result:
The solution for equation 6x-5y=15 and x=y+3 are
x=0 and y=-3.