Question

A wire carries a current of 0.86 A. This wire makes an angle of 70° with respect to a magnetic field of magnitude 5.8 × 10-5 T. The wire experiences a magnetic force of magnitude 8.5 × 10-5 N. What is the length of the wire?

Answer 1

The length of wire is 4.68 m

Step-by-step explanation:

From the question

Current in wire ; I = 0.86 A

Angle ;
`\theta = 70^(o)`

Magnetic Field ;
`B = 5.8 * 10^(-5) T`

Magnetic force ;
`F = 8.5 * 10^(-5) N`

Let length of wire be L,

Now , the formula for force is

`F = I * B * L * sin(\theta)`

rearranged as

`L = (F)/(B * I * sin(\theta))`

Insert the values

`L = (8.5 * 10^(-5)N)/(5.8 * 10^(-5)T * 0.86 A * sin(70^(o)))`

`L = 4.68 m`

So the length of wire is 4.68 m