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A turntable is switched from 11.3 rad/s to 1.9 rad/s, and the platter goes through an angle of 17.95 radian in reaching the new angular speed. What is the angular acceleration of the platter?

A turntable is switched from 11.3 rad/s to 1.9 rad/s, and the platter goes through-example-1
User Motonstron
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1 Answer

19 votes
19 votes

Hi there!

We can use the angular equivalent of the following kinematic equation:


\omega_f^2 = \omega_i^2 + 2\alpha \theta

ωf = final angular velocity (1.9 rad/s)

ωi = initial angular velocity (11.3 rad/s)

α = angular acceleration (? rad/s²)

θ = angular displacement (17.95 rad)

We can rearrange the equation to solve for angular acceleration.


\omega_f^2 - \omega_i^2 = 2\alpha \theta\\\\\alpha = (\omega_f^2 - \omega_i^2)/(2\theta)

Plug in the given values and solve.


\alpha = (1.9^2 - 11.3^2)/(2(17.95)) = \boxed{3.456 (rad)/(s)}

User Sonny D
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