Question

g Given the equation: ee−xx2 (1 + 7xx4) = 1 (i) How many roots does the equation have? (ii) Plot the function over a range of x values to show those roots. (iii) Use the bisection method to find the roots.

Answer 1

Explanation:

(i) We have that

`e^(-x^2(1+7x^4))=1\\ln[e^(-x^2(1+7x^4))]=ln(1)\\-x^2(1+7x^4)=0\\x_(1,2)=0\\x_(3,4,5,6)=\pm (i)/(√(7))`

Hence, there are six roots, two real and four imaginary roots

(ii)

hope this helps!!