Question

The average intensity of light emerging from a polarizing sheet is 0.775 W/m2, and that of the horizontally polarized light incident on the sheet is 0.970 W/m2. Determine the angle that the transmission axis of the polarizing sheet makes with the horizontal.

Answer 1

the transmission axis of polarizing sheet makes an angle of
`\Theta =26.74^(\circ)` with the horizontal

Step-by-step explanation:

We have given that intensity of light incident on the sheet
`I_0=0.970W/m^2`

Average intensity of light emerging from a polarizing sheet
`I=0.775W/m^2`

We have to find the angle between transmission axis with the horizontal

Intensity of light polarizing from sheet is equal to
`I=I_0cos^2\Theta`

So
`0.775=0.970cos^2\Theta`

`cos^2\Theta =0.798`

`cos\Theta =0.893`

`\Theta =26.74^(\circ)`

So the transmission axis of polarizing sheet makes an angle of
`\Theta =26.74^(\circ)` with the horizontal