Question

7. The uranium nucleus contains a charge 92 times that of the proton. If a proton is shot at the nucleus, how large a repulsive force does the proton experience due to the nucleus when it is 1×10-11m from the nucleus? a) 1.1 ×10-4N b) 2.1 ×10-4N c) 1.1 ×10-2N d) 2.1 ×10-2N

Answer 1

2.12 x 10^-4 N

Step-by-step explanation:

charge on uranium nucleus, Q = 92 e

charge on proton, q = e

distance, d = 1 x 10^-11 m

The force between the two charged particles is given by

`F = (KQq)/(d^(2))`

`F = (K* 92 e * e)/(10^(-22))`

e = 1.6 x 10^-19 C

`F = (9* 10^(9)* 92* 1.6* 10^(-19) * 1.6* 10^(-19))/(10^(-22))`

F = 2.12 x 10^-4 N

Thus, the force between the proton and the nucleus of Uranium is 2.12 x 10^-4 N.