Question

A particular RC circuit is assembled from a 12 volt battery, a 300 Ω resistor, and a 73 µF capacitor. How long will it take the capacitor to achieve a charge of 63% of its maximum charge (once turned on)?

Answer 1

`\tau = 0.0219`

Step-by-step explanation:

The time
`\tau` it takes for the voltage across the capacitor
`V_c` to go from 0 volts to 63% of the source voltage is given by the formula:

`\tau= RC`

Where:

`\tau=Time\hspace{3}constant\\R=Electrical\hspace{3}resistance\\C=Capacitance`

After
`5 \tau` the voltage has risen to 99% of its final value.

Therefore:

`\tau =RC=300(73* 10^(-6))=0.0219`