Question

A 0.245 kg ball is thrown straight up from 2.07 m above the ground. Its initial vertical speed is 8.00 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

Answer 1

The work done by gravity is
`4.975 \: Joules`

Step-by-step explanation:

The data given in the question is :

Mass is
`0.245 kg`

Height from ground is
`2.07 m`

As we know , the work done is state function , it depends on initial and final position not on the path followed.

So, work done by gravity = change in potential energy

Work done = Initial potential energy - final potential energy

Insert values from question

Work done =
`mass * gravity * (change \: in \: height)`

Work done =
`0.245 kg * 9.81 m/s^(2) * 2.07 m`

So, work done =
`4.975 Joules`

Hence the work done by gravity is
`4.975 \: Joules`