Question

Light of wavelength 630 nm falls on two slits and produces an interference pattern in which the third-order bright red fringe is 35 mm from the central fringe on a screen 2.8 m away. Part A What is the separation of the two slits?

Answer 1

The separation of the two slits is = 1.5 ×
`10^(-4)` m

Step-by-step explanation:

Wave length
`\lambda` = 630 nm = 0.63 mm

x = 35 mm

l = 2.8 m

Order of fringes (m) = 3

We know that the separation of the two slits is given by

`d = (m \lambda \ l)/(x)`

Put all the values in above formula we get

`d = ((0.63)(3)(2.8))/((35))`

d = 1.5 ×
`10^(-4)` m

Therefore the separation of the two slits is = 1.5 ×
`10^(-4)` m