Answer:
v=8m/s
Step-by-step explanation:
To solve this problem we have to take into account, that the work done by the friction force, after the collision must equal the kinetic energy of both two cars just after the collision. Hence we have
![W_(f)=E_(k)\\W_(f)=\mu N=\mu(m_1+m_1)g\\E_(k)=(1)/(2)[m_1+m_2]v^2](https://img.qammunity.org/2021/formulas/physics/college/804bf1b5x88ww94xxyo3fxghpkf0j6av7a.png)
where
mu: coefficient of kinetic friction
g: gravitational acceleration
We can calculate the speed of the cars after the collision by using

Now , we can compute the speed of the second car by taking into account the conservation of the momentum

the car did not exceed the speed limit
Hope this helps!!