Question

A syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To what temperature must the gas in the syringe be heated/cooled in order to have a volume of 435 mL at 2.50 atm? Group of answer choices

Answer 1

Answer: The temperature to which the gas in the syringe must be heated is 720.5 K

Step-by-step explanation:

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1,V_1\text{ and }T_1` are the initial pressure, volume and temperature of the gas

`P_2,V_2\text{ and }T_2` are the final pressure, volume and temperature of the gas

We are given:

`P_1=1.88atm\\V_1=285mL\\T_1=355K\\P_2=2.50atm\\V_2=435mL\\T_2=?K`

Putting values in above equation, we get:

`(1.88atm* 285mL)/(355K)=(2.50atm* 435mL)/(T_2)\\\\T_2=(2.50* 435* 355)/(1.88* 285)=720.5K`

Hence, the temperature to which the gas in the syringe must be heated is 720.5 K