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A roller coaster car moves around a vertical circle. At the bottom of the circle, the car experiences four times as much radial (centripetal) acceleration as at the top of the circle. Compared to its speed at the top of the circle, the speed of the car at the bottom of the circle is:

A. four times as great.
B. 16 times as great
C. √2 times as great
D. twice as great
E. 2√2 times as great.

1 Answer

3 votes

Answer:

The speed of the car at the bottom of the circle is twice as its speed at the top of the circle.

Step-by-step explanation:

It is given that, at the bottom of the circle, the car experiences four times as much radial (centripetal) acceleration as at the top of the circle such that :


a_B=4* a_T

The centripetal acceleration is given by :


a=(v^2)/(r)

Let
v_B\ and\ a_T are the speed of the roller coaster car at bottom and at top respectively.


(a_B)/(a_T)=4\\\\((v_B^2/r))/((v_T^2/r))=4\\\\(v_B^2)/(v_T^2)=4\\\\(v_B)/(v_T)=2\\\\v_B=2* v_T.

So, the speed of the car at the bottom of the circle is twice as its speed at the top of the circle. Hence, the correct option is (D).