Question

A car of mass 980.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 37.4 km/hr (10.4 m/s), the net power which the engine supplies is 5500.0 W (in addition to the extra power required to make up for air resistance and friction). Calculate the acceleration of the car at that time.

Answer 1

Acceleration will be equal to
`acceleration=0.5396m/sec^2`

Step-by-step explanation:

We have given mass of the car m = 980 kg

Velocity of the car v = 37.4 km/hr = 10.4 m/sec

Power supplied by the engine P = 5500 watt

We know that power is rate of change of energy with respect to time

So
`Power=(energy)/(time)`

Energy is equal to energy = force × distance

So
`Power=(force* distance)/(time)`

From newtons second law force is equal to Force = mass × acceleration

So
`Power=mass* acceleration* (distance)/(time)`

`Power=mass* acceleration* velocity`

So
`5500=980* acceleration* 10.4`

`acceleration=0.5396m/sec^2`