Question

How many moles of \ce{CO2}COX

2

​
will be produced from 72.0 \text{ g}72.0 g72, point, 0, start text, space, g, end text of \ce{CH4}CHX
4

​
assuming \ce{O2}OX
2

​
is available in excess?

Answer 1

1.24

Step-by-step explanation:

Khan Academy 2021

Answer 2

4.5 moles of carbon dioxide

Step-by-step explanation:

Given parameters:

Mass of CH₄ = 72g

Unknown:

number of moles of CO₂ produced = ?

Solution:

To solve this problem, let us write the reaction equation first;

CH₄ + 2O₂ → CO₂ + 2H₂O

Now we know that O₂ is in excess and CH₄ is the limiting reactant that will determine the extent of the reaction.

Let us find the number of moles of CH₄ ;

Number of moles =
`(mass)/(molar mass)`

molar mass of CH₄ = 12 + 4 = 16g/mol

Number of moles =
`(72)/(16)` = 4.5moles

From the reaction equation;

1 mole of methane produced 1 mole of carbon dioxide

4.5 moles of methane will produce 4.5 moles of carbon dioxide