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What are the solutions of 6x^2+2x-20=0

User Mardok
by
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1 Answer

3 votes

Answer:

5/3, -2

Explanation:

First to make it easeir you must simplify it.

Divide both sides by 2

3x^2+x-10=0

Next factor the expression

(x+2)(3x-5)=0

Then set both sides to 0

(x+2)=0

(3x-5)=0

Then solve for each

(x+2)=0 -> x=-2

(3x-5)=0 -> 3x=5 -> x=5/3

User Thkang
by
5.2k points