Question

A gas is collected by water displacement so that its partial pressure is 72.92 kPa. The total pressure of the gas over water is 75.02 kPa. What is the temperature at which the gas was collected?

Answer 1

18.5 degree Celsius

Step-by-step explanation:

We are given that

Partial pressure of gas=
`P_1`=72.92 KPa

Total pressure gas =P=75.02 KPa

We have to find the temperature at which the gas was collected.

We know that

Total pressure,P=
`P_1+P_2`

`P_2=P-P_1=75.02-72.92=2.1 KPa`

Water vapor pressure=
`P_2=2.1 KPa`

`P_2=(2.1* 760)/(101.3)mm Hg=15.76mm Hg`

101.3 KPa=760 mm Hg

Temperature when water vapor pressure is 15.75 mm Hg=18.5 degree Celsius

The temperature at which gas collected=18.5 degree Celsius