Question

A 47.5-turn circular coil of radius 5.25 cm can be oriented in any direction in a uniform magnetic field having a magnitude of 0.535 T. If the coil carries a current of 26.9 mA, find the magnitude of the maximum possible torque exerted on the coil.

Answer 1

Torque,
`5.91* 10^(-3)\ N-m`

Step-by-step explanation:

Given that,

The number of turns in the coil, N = 47.5

Radius of the coil, r = 5.25 cm

Uniform magnetic field, B = 0.535 T

Current in the coil, I = 26.9 mA

The magnitude of the maximum possible torque exerted on the coil isg given by :

`\tau=NIAB\\\\\tau=47.5* 26.9* 10^(-3)* \pi (5.25* 10^(-2))^2* 0.535 \\\\\tau=0.00591\ N-m\\\\\tau=5.91* 10^(-3)\ N-m`

So, the magnitude of the maximum possible torque exerted on the coil is
`5.91* 10^(-3)\ N-m`.