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In a different plan for area​ codes, the first digit could be any number from 0 throughnbsp 5​, the second digit was either 6, 7, 8​, and the third digit could be any number except bsp 3nbsp bsp or 4. With this​ plan, how many different area codes are​ possible?

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Answer:

There are 144 different area codes possible

Explanation:

To solve this problem, we need to know how many possibilities are for each number, and them multiply them:

For the first digit, there are 6 possibilities (0,1,2,3,4,5);

For the second digit, there are 3 possibilities (6,7,8);

For the third digit, there are 8 possibilities (0,1,2,5,6,7,8,9).

So, the number of different area codes are 6*3*8 = 144

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