Question

If the rate of decrease for the partial pressure of N2H4N2H4 in a closed reaction vessel is 70 torr/htorr/h , what is the rate of change for the partial pressure of NH3NH3 in the same vessel

Answer 1

`r_(NH_3)=140torr/h`

Step-by-step explanation:

Hello,

In this case, the undergoing chemical reaction is:

`N_2H_4 (g) + H_2 (g) \rightarrow 2 NH_3`

Thus, in terms of pressures, the rate becomes:

`-r_(N_2H_4)=(1)/(2) r_(NH_3)`

Thus, the rate of change for the partial pressure of ammonia turns out:

`r_(NH_3)=2*(-r_(N_2H_4))\\r_(NH_3)=2*[-(-70torr/h)]\\r_(NH_3)=140torr/h`

The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.

Best regards.