141k views
5 votes
The lab just ran out of 1 M HCl that you need to complete the Benzillic Acid lab. The TA tells you there is 12 M HCl in the fume hood. You need to make 10.0 mL of 1.0 M HCl. What volume or 12 M HCl will you need to dilute to get the correct volume and concentration of 1.0 M HCl?

User Cgvoller
by
7.4k points

1 Answer

7 votes

Answer:

0.83 mL

Step-by-step explanation:

Given data

  • Initial concentration (C₁): 12 M
  • Initial volume (V₁): ?
  • Final concentration (C₂): 1.0 M
  • Final volume (V₂): 10.0 mL

We can calculate the initial volume of HCl using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 1.0 M × 10.0 mL / 12 M

V₁ = 0.83 mL

The required volume of the initial solution is 0.83 mL.

User Tounano
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.