Question

The Wolff-Kishner reaction involves the reaction of an aldehyde/ketone with hydrazine in the presence of KOH. The process is useful for converting an aldehyde or ketone into an alkane. The reaction involves formation of a hydrazone, followed by base-catalyzed double-bond migration, loss of N2 gas to give a carbanion, and protonation to give the alkane. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions

Answer 1

in the attached image is the reaction mechanism.

Step-by-step explanation:

The first reaction (reaction 1) shown in the attached image is the Wolff-Kishner reduction, which is characterized when the carbonyl is reduced to an alkane in the presence of a hydrazine and a base. In reaction 1, the aldehyde reacts with hydrazine to produce oxime. This mechanism begins with the attack of the amine on the carbonyl group. Proton exchange happens and the water leaves the molecule.

In reaction 2, the KOH is deprotoned in nitrogen and organized to form the bond between the nitrogen molecule. this deprotonation releases the nitrogen gas