Question

Part APart complete A sample of sodium reacts completely with 0.568 kg of chlorine, forming 936 g of sodium chloride. What mass of sodium reacted? Express your answer to three significant figures and include the appropriate units.

Answer 1

Answer: 368 grams of sodium reacted.

Step-by-step explanation:

The balanced reaction is :

`2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)`

`\text{Moles of chlorine}=\frac{\text{given mass}}{\text{Molar Mass}}`

`\text{Moles of chlorine}=(0.568* 1000g)/(71g/mol)=8moles`

`\text{Moles of sodium chloride}=(936g)/(58.5g/mol)=16mol`

According to stoichiometry :

2 moles of
`NaCl` are formed from = 2 moles of
`Na`

Thus 16 moles of
`NaCl` are formed from=
`(2)/(2)* 16=16moles` of
`Na`

Mass of
`Na=moles* {\text {Molar mass}}=16moles* 23g/mol=368g`

Thus 368 grams of sodium reacted.