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A circular specimen of MgO is loaded using a three-point bending mode. Compute the minimum possible radius of the specimen without fracture, given that the applied load is 500 N (112 lbf), the flexural strength is 105 MPa (15,000 psi), and the separation between load points is 50.0 mm (1.97 in.).

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Answer:

The value of minimum possible radius of the specimen without fracture


r = 4.23 mm

Step-by-step explanation:

Given data

Applied load F = 500 N

Flexural strength = 105 M Pa

Separation between load points = 50 mm

The minimum possible radius of the specimen without fracture is given by


r_} = \sqrt[3]{((500) (50))/((105) (3.14) ) }


r = 4.23 mm

This is the value of minimum possible radius of the specimen without fracture.

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