Question

Factor 16x4 - 4y2

A) (x + 4y)(x - 4y)
B) 4(2x2 + y)(2x2 - y)

Answer 1

B

Explanation:

16x⁴- 4y²

= 4( 4x⁴ -y²) (factorise common factor of 4)

= 4 [(2x²)² -y²]

= 4 (2x² +y)(2x² -y)

*a² -b²= (a+b)(a-b)

Answer 2

Explanation:

`16 {x}^(4) - 4 {y}^(2) \\ {4}^(2) {x}^(4) - {2}^(2) {y}^(2) \\ {4}^(2) {x}^(2) * {x}^(2) - {2}^(2) {y}^(2) \\ (4 {x}^(2) - 2y)(4 {x}^(2) - 2y)`