Answer:
The mean of this sampling distribution is 63.5 and the standard deviation of this sampling distribution is 0.5
Explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
![\mu = 63.5, \sigma = 2.5, n = 25, s = (2.5)/(√(25)) = 0.5](https://img.qammunity.org/2021/formulas/mathematics/college/9kh73fbqka30gu5xkd1ty6266gpr1t9c8f.png)
So the correct answer is:
The mean of this sampling distribution is 63.5 and the standard deviation of this sampling distribution is 0.5