Question

An astronaut on a small planet wishes to measure the local value of g by timing pulses traveling down a wire which has a large object suspended from it. Assume a wire of mass 3.60 g is 1.60 m long and has a 3.00-kg object suspended from it. A pulse requires 60.1 ms to traverse the length of the wire. Calculate gplanet from these data. (You may neglect the mass of the wire when calculating the tension in it.)

gplanet = m/s2

Answer 1

`0.53m/s^2`

Step-by-step explanation:

We are given that

Mass of wire=m=3.6 g=
`3.6* 10^(-3) kg`

1 kg=1000 g

Length of wire=l=1.6 m

Mass of object=m'=3 kg

Time,t=60.1 ms=
`60.1* 10^(-3) s`

`1 ms=10^(-3) s`

Speed,v=
`(distance)/(time)=(1.6)/(60.1* 10^(-3))=26.62 m/s`

`g=(v^2m)/(m'l)`

Using the formula

`g=((26.62)^2* 3.6* 10^(-3))/(3* 1.6)=0.53m/s^2`