Answer:
4.66×10^-6J
Step-by-step explanation:
The capacitance of a capacitor is given by:
C= ε A/d
ε= permittivity of free space
A= Area of the plates
d= distance between the plates.
A= (8.1×10-2)^2= 65.61×10^-4m2
d= 1.9× 10^-3m
ε= 8.85×10^-12
C= 8.85×10^-12 × 65.61×10^-4/1.9× 10^-3
C= 3.1×10^-11 F
Energy stored in a capacitor= q^2/2C
But q= 17×10-9
E= (17×10^-9)^2/2×3.1×10^-11
E= 4.66×10^-6J