Question

Jim strikes a 0.058 kg golf ball with a force of 272 N, giving it a velocity of 62.0 m/s. How long was the ball in contact with the club?

Answer 1

The question is about finding the time of contact between a golf club and a ball using the concepts of impulse and momentum in physics.

Step-by-step explanation:

The student is asking how long a golf ball was in contact with the club after being struck with a force to give it a specific velocity. This question involves the concepts of impulse and momentum in physics. The impulse experienced by the ball is equal to the change in momentum. To find the time of contact, we can use the relation: impulse = average force × time. We already know the force and the final velocity of the ball. We can use the mass of the ball and its final velocity to find the change in momentum, as initial velocity is considered zero right before impact.

First, we calculate the change in momentum (final momentum - initial momentum), which is mv (mass × velocity), since the initial velocity is zero just before the strike. Next, we can rearrange the impulse equation to solve for time:

time = impulse / average force

The impulse is the product of mass and velocity, and by dividing this by the average force, we obtain the time.

Answer 2

Answer: 0.013 seconds

Step-by-step explanation:

Given that

Mass of golf ball = 0.058 kg

Force = 272 N

Velocity = 62.0 m/s

Time taken = ?

Recall that force is the rate of change of momentum per unit time

i.e Force = Change in momentum / Time

i.e Force = (Mass x velocity) / Time

272N = (0.058 kg x 62.0 m/s) / Time

272N = 3.6kgm/s / Time

Time = (3.6kgm/s / 272N)

Time = 0.013 seconds

Thus, the ball was in contact with the club for 0.013 seconds