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In the decomposition of water, how many grams of hydrogen gas and oxygen gas are produced from 23.44 g of water?

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Answer:

2.60 g of H₂ and 20.8 g of O₂ are produced in the decomposition of 23.44 g of water

Step-by-step explanation:

Water decomposition is:

2H₂O → 2H₂ + O₂

We convert the mass of water, to moles:

23.44 g . 1 mol/18 g = 1.30 moles

Ratio is 2:2 with hydrogen and 2:1 with oxygen. Let's make rules of three:

2 moles of water can produce 2 moles of hydrogen gas and oxygen gas

Then, 1.30 moles will produce:

(1.30 . 2) /2 = 1.30 moles of H₂

(1.30 . 1) /2 = 0.65 moles of O₂

We convert the moles to mass

1.30 moles of H₂ . 2g / 1mol = 2.60 g of H₂

0.65 moles of O₂ . 32 g / 1 mol = 20.8 g of O₂

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