Question

Monochromatic light falls on two narrow slits that are 0.05 mm apart. The second order bright fringe appears 12 cm from the center maximum on a screen 5 meters away. What is the wavelength of the incident light?

Answer 1

λ = 1.2 x 10⁻⁶ m

Step-by-step explanation:

Given that,

slit separation, d = 0.050 mm

= 5 x 10⁻⁵ m

Distance between the fringes, D = 5.00 m

distance between the fringes, x = 12.0 cm

= 0.12 m

wavelength of the light = ?

the separation between the fringe is given by

`x = (n\lambda\ D)/(d)\\\\\lambda = (x d)/(n\ D)\\`

where as n = 1

`\lambda = (0.05* 10^-^3* 0.12)/(1* 5.00)`

λ = 1.2 x 10⁻⁶ m