Question

1.A bullet is fired with a velocity of 50m/s at an angle tita to the

horizontal.
a) what is the value of tita for maximum range with this velocity.
b) calculate the maximum range. ​

Answer 1

Speed = 50 m/s

50cos45

o

=vcos30

o

v=

1.732

50×1.414

​

v=40.82m/s

v

2

=u

2

−2gh

v

2

sin

2

30=(50)

2

sin

2

45−2×10×h

h=41.66m

h=

3

125

​

m

Step-by-step explanation:

hope this helps!