Question

4. A given mass of nitrogen at room temperature occupies a volume of 4.50 L at 1.25 atm pressure.

What will be the volume if the pressure is increased to 2.00 atm?

Answer 1

Answer: 2.81 litres

Step-by-step explanation:

Given that:

initial volume of nitrogen V1 = 4.50L

initial pressure P1 = 1.25 atm

new volume V2 = ?

new pressure P2 = 2.00 atm

Since, only pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

1.25 atm x 4.50L = 2.00 atm x V2

5.625 = 2.00V2

Divide both sides by 2.00

5.625/2.00 = 2.00V2/2.00

2.8125L = V2 (rounded to the nearest hundredth as 2.81 liters)

The new volume of nitrogen will be 2.81 litres