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In ΔDEF, the measure of ∠F=90°, the measure of ∠E=32°, and FD = 9.6 feet. Find the length of EF to the nearest tenth of a foot.

User Fsarter
by
4.9k points

2 Answers

1 vote

Answer:

EF=15.4 ft

Explanation:

I got it right on delta math so ig its right

User Cudos
by
4.8k points
7 votes

Answer:


EF=15.4\ ft

Explanation:

we know that

In the right triangle DEF


tan(E)=(FD)/(EF) ----> by TOA (opposite side divided by adjacent side)

substitute the given values


tan(32^o)=(9.6)/(EF)

solve for EF


EF=(9.6)/(tan(32^o))=15.4\ ft

User Braulio
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