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You are a meteorologist. While taking present weather observations, you note that the sky is full of wispy cirrus clouds estimated to be about 8 kilometers (km) overhead. If a warm front is approaching from the south, has a slope of 1:300 and is moving toward you at an average warm-front speed of about 40 km/hour, it will it take -------hours to pass your area?

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Answer:

It will take 60 hours to pass your area

Step-by-step explanation:

From the question we are told that

The the distance of wispy cirrus clouds is
d_w =6km = 6*10^3 m

The slope is given as
S = 1:300 = (1)/(300)

The speed is
v = 40km/hour

Since the slope is 1:300 which indicates the change in the distance of the wispy cirrus clouds overhead to the distance of the warm front

Now if

1 km → 300 km

Then


8km → x km

Cross multiplying and making x the subject


x = 8 *300 = 2400 \ km

Velocity is mathematically denoted as


velocity(v) = (Distance(d) )/(Time(t) )

Now making time the subject


Time (t) = (Distance )/(Velocity)

Now substituting values we have


t =(2400)/(40)


= 60\ hours

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