Question

Enter your answer in the provided box. Consider the reaction: N2(g) + 3H2(g) → 2NH3(g) Suppose that a particular moment during the reaction, molecular hydrogen is reacting with a magnitude of 0.0759 M/s. At what rate is molecular nitrogen reacting?

Answer 1

0.0253 M/s

Step-by-step explanation:

From the reaction

N₂ + 3H₂ → 2NH₃

The rate of reaction can be written as

Rate = -
`(d[N_2])/(dt)` = -
`(1)/(3) (d[H_2])/(dt)` = +
`(1)/(2) (d[NH_3])/(dt)`

From the above rate equation we can conclude that the rate of reaction of N₂ is equal to one third of the rate of reaction of H₂,

So,

Rate of reaction of molecular nitrogen =
`(1)/(3) * 0.0759`

Upon calculation, we get rate of reaction of molecular nitrogen = 0.0253 M/s