Question

2[x + 5(6 - x) + 16] - 11 = 49 - 10x solve for x

Answer 1

Answer:
`x = -16`

Simplifying

`2[x + 5(6 + -1x) + 16] + -11 = 49 + -10x`

`2[x + (6 * 5 + -1x * 5) + 16] + -11 = 49 + -10x`

`2[x + (30 + -5x) + 16] + -11 = 49 + -10x`

Reorder the terms

`2[30 + 16 + x + -5x] + -11 = 49 + -10x`

Combine like terms: 30 + 16 = 46

`2[46 + x + -5x] + -11 = 49 + -10x`

Combine like terms: x + -5x = -4x

`2[46 + -4x] + -11 = 49 + -10x`

`[46 * 2 + -4x * 2] + -11 = 49 + -10x`

`[92 + -8x] + -11 = 49 + -10x`

Reorder the terms

`92 + -11 + -8x = 49 + -10x`

Combine like terms: 92 + -11 = 81

`81 + -8x = 49 + -10x`

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '10x' to each side of the equation

`81 + -8x + 10x = 49 + -10x + 10x`

Combine like terms: -8x + 10x = 2x

`81 + 2x = 49 + -10x + 10x`

Combine like terms: -10x + 10x = 0

`81 + 2x = 49 + 0`

`81 + 2x = 49`

Add '-81' to each side of the equation.

`81 + -81 + 2x = 49 + -81`

Combine like terms: 81 + -81 = 0

`0 + 2x = 49 + -81`

`2x = 49 + -81`

Combine like terms: 49 + -81 = -32

`2x = -32`

Divide each side by '2'.

`x = -16`