Question

According to an​ article, 36​% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly selected​ adults, find the probability that the​ number, X, who have experienced a breakup at least once during the last 10 years is

Answer 1

Title:

See the explanation.

Explanation:

The probability that an adult will experience breakup at least once during the last ten years is
`(36)/(100) = 0.36`.

Hence, the probability that the adult will not experience breakup is (1 - 0.36) = 0.64.

As per the given question, X is the number of adults who face breakup. From the 9 people X persons can be chosen in
`^9C_X` ways.

The probability that X persons will experience breakup is
`^9C_X * (0.36)^X * (0.64)^(9 - X)`.