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The exact value of tan5pi/12 is

User Kevin Mann
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Answer:

Explanation:

This is the sum identity for tangent(x + y), where x and y are angles measured in radians. The formula for tan(x + y) is
(tan(x)+tan(y))/(1-tan(x)tan(y))

The first order of business is to find which 2 angles, when expressed in terms of the denominator 12, add up to equal
(5\pi)/(12)

We will use the first quadrant angles, and only the "important" ones:


(\pi)/(4),(\pi)/(3),(\pi)/(6),(\pi)/(2),\pi

When expressed in terms of the denominator of 12, these angles have the equivalent angles, in order from above:


(3\pi)/(12),(4\pi)/(12),(2\pi)/(12),(6\pi)/(12),(12\pi)/(12)

We need to find the 2 whose numerators add up to a 5. That would be:


(3\pi)/(12) +(2\pi)/(12)=(5\pi)/(12)

Remember that


(3\pi)/(12)=(\pi)/(4) and
(2\pi)/(12)=(\pi)/(6) so

angle x is
(\pi)/(4) and angle y is
(\pi)/(6), making our tangent sum:


tan((\pi)/(4)+(\pi)/(6))

Filling that into our formula for the sum of tan(x + y):


tan((\pi)/(4)+(\pi)/(6))=(tan((\pi)/(4))+tan((\pi)/(6)) )/(1-tan((\pi)/(4))tan((\pi)/(6)) )

It just so happens that


tan((\pi)/(4))=1 and


tan((\pi)/(6))=(√(3) )/(3) so our formula then becomes


tan((\pi)/(4)+ (\pi)/(6))=(1+(√(3) )/(3) )/(1-(1)((√(3) )/(3)) ) which simplifies to


((3+√(3) )/(3) )/((3-√(3) )/(3) ) and then bring up the lower fraction and flip it to multiply giving you:


tan((\pi)/(4) +(\pi)/(6) )=(3+√(3) )/(3-√(3) )

I have the feeling that you need to rationalize that denominator, and if you do that, the final answer will be:


2+√(3)

I know I kind of left you hanging at the very end with rationalizing, but there was so much already that went into this problem in such depth, that I didn't want to risk possibly confusing you even more than I may have already done so. Try and follow the best that you can.

User MAV
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