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A 1.45-kg block is pushed against a vertical wall by means of a spring (k = 860 N/m). The coefficient of static friction between the block and the wall is 0.36. What is the minimum compression in the spring to prevent the block from slipping down? g

User Windsinger
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1 Answer

2 votes

Answer:

The minimum compression in the spring is
d=0.0459m

Step-by-step explanation:

From the question we are told that

The mass of the block is
m_b = 1.45kg

The spring constant is
k =860 N/m

The coefficient of static friction is
\mu = 0.36

The mathematical relationship between the wight of the block and the force exerted by the spring is


W_b = F_s

Where
W_b is mathematical represented as
W_b = mg and


F_s is mathematically represented as
F_s = \mu * k *d

Where d is minimum length of compression in the spring to prevent the block from slipping

Now the relation can be wrtten as


mg = \mu *k * d

making d the subject we have


d = (mg)/(\mu * k)


= (1.45* 9.8 )/(0.36 *860)


d=0.0459m

User Michael Mangold
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