What is the potential energy of a spring that is stretched 0.15 m from equilibrium and has a spring constant of 0.55 N/m?

asked Jun 28, 2021 13.7k views

5 votes

7.2k points

Please log in or register to add a comment.

3 votes

Step-by-step explanation:

EE = ½ kx²

EE = ½ (0.55 N/m) (0.15 m)²

EE = 0.62 J

7.2k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.3m questions

10.9m answers