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What is the potential energy of a spring that is stretched 0.15 m from equilibrium and has a spring constant of 0.55 N/m?
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What is the potential energy of a spring that is stretched 0.15 m from equilibrium and has a spring constant of 0.55 N/m?

User Doguita
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1 Answer

3 votes

Step-by-step explanation:

EE = ½ kx²

EE = ½ (0.55 N/m) (0.15 m)²

EE = 0.62 J

User Joseph Zabinski
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