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A coil of wire with 60 turns lies on the plane of the page, and a uniform magnetic field points into the page with a strength of 1.10 T. The coil has an initial area of 0.890 m2 and is then elongated so that its area decreases to 0.270 m2 in 0.80 s. What is the magnitude of the average induced emf in the coil while its area is changing? 59.334 Incorrect: Your answer is incorrect. V

User Knarz
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1 Answer

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Answer:

0.85V

Step-by-step explanation:

The emf is calculated by using the Lenz's Law


\epsilon=-(\Delta\Phi_B)/(\Delta t)

But for this case we have that the magnetic field is constant. Hence we have


\epsilon=-(B(A_(2)-A_(1)))/(t_2-t_1)=-((1.10T)(0.270m^(2)-0.89m^(2)))/(0.8s)\\\\\epsilon=0.85V

where we have taken that the intial time is t1=0

I hope this is useful for you

regards

User Maxdownunder
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