Answer:
Magnification will be equal to 3
Step-by-step explanation:
We have given focal length of the converging lens
![F_1=20cm](https://img.qammunity.org/2021/formulas/physics/college/cm7ci8u0tp5wlxu6t5uq9uhgjihk5v8r6v.png)
Focal length of the diverging lens
![F_2=30cm](https://img.qammunity.org/2021/formulas/physics/college/tq9yf007fw8m0yw10pugp17n3wt5gj8d5m.png)
Object is placed 40 cm to the length of the converging lens d = 40 cm
Combination of the focal length will be equal to
![(1)/(F)=(1)/(F_1)+(1)/(F_2)](https://img.qammunity.org/2021/formulas/physics/college/7n0j28oabzuemyt0bxedyb3m09kq5rhavd.png)
![(1)/(F)=(1)/(20)+(1)/(-30)=(1)/(20)-(1)/(30)=(1)/(60)](https://img.qammunity.org/2021/formulas/physics/college/5vg86hj286xfjjbksjck7r4aa1ny15o991.png)
F = 60 cm
So combination of the focal length will be 60 cm
Magnification is given by
![M=(F)/(F-d)=(60)/(60-40)=3](https://img.qammunity.org/2021/formulas/physics/college/lcbo2drf1b4qkwihh054gwajx0hq4j5nao.png)
So magnification will be equal to 3