Question

A car with a mass of 3,272 kg is rolling on a level road at 33.0 m/s. It receives an impulse with a magnitude of 8,411 N-s and its speed is reduced as much as possible by an impulse of this size. What was the car's speed after the impulse was applied

Answer 1

The car's speed after the impulse was applied is 35.57 m/s.

Step-by-step explanation:

Given that,

Mass of the car, m = 3272 kg

Initial speed of the car, u = 33 m/s

Impulse received by the car, J = 8,411 N-s

Let v is the car's speed after the impulse was applied. Impulse is equal to the change in momentum. So,

`J=m(v-u)\\\\v=(J)/(m)+u\\\\v=(8411)/(3272)+33\\\\v=35.57\ m/s`

So, the car's speed after the impulse was applied is 35.57 m/s.